64+64a=-7a^2

Solution for 64+64a=-7a^2 equation:

64+64a=-7a^2

We move all terms to the left:

64+64a-(-7a^2)=0

We get rid of parentheses

7a^2+64a+64=0

a = 7; b = 64; c = +64;
Δ = b2-4ac
Δ = 642-4·7·64
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-48}{2*7}=\frac{-112}{14}
=-8
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+48}{2*7}=\frac{-16}{14}
=-1+1/7
$